6y^2=0.24

Solution for 6y^2=0.24 equation:

6y^2=0.24

We move all terms to the left:

6y^2-(0.24)=0

We add all the numbers together, and all the variables

6y^2-0.24=0

a = 6; b = 0; c = -0.24;
Δ = b2-4ac
Δ = 02-4·6·(-0.24)
Δ = 5.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{5.76}}{2*6}=\frac{0-\sqrt{5.76}}{12}
=-\frac{\sqrt{}}{12}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{5.76}}{2*6}=\frac{0+\sqrt{5.76}}{12}
=\frac{\sqrt{}}{12}
$